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Given f(x) = 10- 16/x, find all c in the interval [-2,8] that satisfies the Mean Value Theorem.
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Begin by taking the derivative ...
16/c^2 ?
Now find the slope using (-2, f(-2)) and (8, f(8))
i plug the -2 and 8 into the original equation for the top part correct?
Yes, plug both -2 and 8 into the equation.
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For f(8) = 10 - 16/8 = 8
is the slope one?
Where to show my work? f(-2) = 10 + 8 = 18 Slope of (-2, 18) and (8,8) is (18-8)/(-2 - 8) = -1 correct?
oh ok yeah i was adding the bottom ones
Set your first answer equal to -1 and solve for c ...
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wait which one sorry
16/c^2 = -1
We have the slope of the endpoints equal to your derivative
got it thanks
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