Question

can someone check my work?
-3x^2 -4x-4=0
(quadratic formula)
x=-(-4) sqr -4 - 4(-3)(-4)/2(-3)
x=-(-4) sqr 16-48/-6
x=4 sqr 32/-6
x=4 sqr4sqr root of 2/-6
x= 2 sqr 2sqr root of 2/3

Answer 1

first, the equation turns out to be a complex root

Answer 2

\[x = 2/3 (-1-i \sqrt(2))\]

Answer 3

\[x = 2/3 (-1+i \sqrt(2))\]

Answer 4

ok so the 2i\[\sqrt{2}\] is going to be positive?

Answer 5

yh, that's a complex number with a complex solution