Question

im stuck on this problem : Solve 3x^2 = –12x – 15

Answer 1

Let's simplify this; do we want to divide both sides by 3?

Answer 2

yea

Answer 3

What would we get then? :)

Answer 4

x^2 +6x-5

Answer 5

That's right:\[3x^2 = –12x – 15,\]\[x^2+4x+5=0.\]We moved everything to the left side. Now, do you know how to factor that?

Answer 6

yeah hold on

Answer 7

ok so any negative number is "i
"

Answer 8

Very close!\[\frac{-4\pm\sqrt{16-20}}{2}=-2\pm i\](remember that \(\sqrt{-1}=i\)).

Answer 9

thanks!