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Mathematics 6 Online
OpenStudy (anonymous):

How many arrangements can be made by the letters of the word DEFINITION a) if the letters i do not occupy the first or last place, (ii) if the letters i are together?

OpenStudy (anonymous):

moi do you have any idea how to do this?

OpenStudy (anonymous):

LOL i did what you did but according to the solution booklet the answer is not correct. The answer is supposed to be 141, 120. any ideas how they got this???????

OpenStudy (anonymous):

You can always write a Python script to answer these types of questions.

OpenStudy (anonymous):

for the first one I got 1693440

OpenStudy (anonymous):

my answer is wrong though because I'm double counting

OpenStudy (anonymous):

yes the answer is supposed to be 141120. hahaha the comma is supposed to make it easier to read. LOL how did you know i was from a different country? hehe

OpenStudy (anonymous):

symbol overloading! ah

OpenStudy (anonymous):

oh wow i didn't know

OpenStudy (anonymous):

definition word has 10 letters a)_ _ _ _ _ _ _ _ _ _ first and last can't be 'i' so we can use only 7 letters for first ant last place (because we have 3 'i') 7 _ _ _ _ _ _ _ _ _ and for last place only 6 are left 7 _ _ _ _ _ _ _ _ 6 now we can use all letters but 2 letters were already used so again we have 8 letters 7 8 _ _ _ _ _ _ _ 6 now 7 7 8 7 _ _ _ _ _ _ 6 now 6 7 8 7 6 _ _ _ _ _ 6 and until 1 7 8 7 6 5 4 3 2 1 6 and you need to multiply all those numbers but we have repeated letters: 'i' is repeated 3 times and 'n' is repeated 2 times, so we count them once than more. to avoid this we need to divide answer by 3!=6 (because 'i' is repeated 3 times) and 2!=2 (because 'n' is repeated 2 times) so answer is 7*8*7*6*5*4*3*2*1*6/6/2

OpenStudy (anonymous):

b) we can group two 'i' letters as one as we would have II D E F I N T O N so now we have 9 spaces and it would be just 9*8*7*6*5*4*3*2*1 but we again double counted however this time only letter N is double counted so we need to divide by 2!=2 and answer is 9*8*7*6*5*4*3*2*1/2=181440

OpenStudy (anonymous):

is it correct answer? :D

OpenStudy (anonymous):

i don't think so

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