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Mathematics 9 Online
OpenStudy (anonymous):

In how man ways can 4 people be accommodated if there are 4 rooms available?

OpenStudy (anonymous):

*how many ways

OpenStudy (ash2326):

let these dashes represent the rooms _ _ _ _ first room can be occupied by one person , select one person from 4 = 4C1=4 second room , we are left with 3 persons =3C1 third room , we are left with 2 persons=2C1 for fourth room=1C1 so 4C1*3C1*2C1*1C1=24 ways

OpenStudy (anonymous):

4*3*2*1 if all rooms are same quality :D

OpenStudy (anonymous):

4P4 or just 4! :D

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