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lim x--> infinity ((7-x^3)/(2x^3-5x))
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= (7/x^30 - 1 ----------- = 0-1 2 - (5/x) --- = -1/2 2-0
first line : - thats (7/x^3) - 1
is it 2x^3-5x}\]? \[\lim_{x\rightarrow \infty}\frac{7-x^3}{2x^3-5x}\]?
yeah
ok, what jimmyrep said
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thank you :)
yw - thnx for confirming satellite - my knowledge of limits is improving i've always found them the most difficult part of calculus
Nice job jimmy
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