Question

Simplify i^67

Answer 1

\[i^{67}=i^{4(16)+3}=i^3\]
that should help
always divide by 4 and look at the remainder

Answer 2

\[i^{67} = i ^{4(16)}*i^3= (1)*(-i)\]

Answer 3

\[\therefore i^{67}=-i\]

Answer 4

Thankyou!

Answer 5

no p!