Question

Hey guys, try this one
if x satisfied 2^(3x^2)+2^[(x^2)+1]is greater or equal to 2^[(3x^2)+2]-5*2^(2x^2) find x

Answer 1

\[2^{3x ^{2}}+2^{x ^{2}+1} \ge 2^{3x ^{2}+2}-5*2^{2x ^{2}}\]

Answer 2

Hmmm ... should we combine the 2^(x^2) on one side and factor them?

\[2 ^{3x^2}(1-4) \ge -2^{x ^{2}+1}-5\times2^{2x ^{2}}\]

Answer 3

yes, well sorry this pb is answered in math groups
the answer is \[x \in [-1,1]\]