Question

integrate x^2 cos x^3
which method most suitable?
by part or substitution??

Answer 1

sub!
let u=x^3
=> du=3x^2 dx

Answer 2

how about
\[\int\limits_{}^{}(x^2)dx/ \sqrt{1- (x-1)^2}\]
hint: \[x-1=\sin \theta\]

Answer 3

\[=\int\limits x^{2}cosu*\frac{du}{3x^{2}} \]
\[= \frac{1}{3} \int\limits cosu du \]
\[= \frac{1}{3} *sinu + c\]
\[= \frac{1}{3} *sinx^3 + C\]

Answer 4

nikvist can u hlp

Answer 5

i was lurning si and stuff like that