Question

How is a pendulum useful? besides keeping time.

Answer 1

testing the gravitational field in an area

Answer 2

the period T is\[T=2\pi\sqrt{\frac{L}{g}\]where L is the length of the pendulum and g is the gravitational field

Answer 3

can you read that? I think my server is acting up :/

Answer 4

yeah, haha it's fine but thank you for helping me!

Answer 5

supposed to be
T=2pi*sqrt(L/g)
sorry

Answer 6

\[\Large T = 2\pi \sqrt {\frac{L}{g}} \]

Answer 7

I can't use LaTeX right now it looks like, oh well.

Answer 8

That's alright, just continue being right in all your answers and that should be enough ;)

Answer 9

Good motto!