Question

What is the equation of the line tangent to the graph of y= x + e^x at x = 0?

Answer 1

at x=0 y=1. so the tangent passes through this point.
to find the slope of the line use differential calculus
dy/dx is the slope
dy/dx = 1 + e^x
at x= 0 dy/dx = 2
so the equation of line is y = 2x + c
c can be found by substituting (0,1) in the equation.