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Mathematics 11 Online
OpenStudy (anonymous):

solve x^3+1=0

OpenStudy (anonymous):

x=-1

OpenStudy (anonymous):

do want only real solutions ? as there are some complex solutions also..

OpenStudy (slaaibak):

you can factorize it first: (x + 1)(x^2 - x + 1)=0 For real solutions, set x+1=0 For complex solutions, set (x^2 - x + 1) Since b^2 - 4ac is negative

OpenStudy (slaaibak):

For complex solutions, set (x^2 - x + 1)=0 **

OpenStudy (anonymous):

is it 1+or- i square root 3/2?

OpenStudy (anonymous):

both the equation has three roots. one real and two complex

OpenStudy (anonymous):

so what does x=

OpenStudy (anonymous):

sorry the roots are 1/2 + i sqrt(3/2) 1/2 - i sqrt (3/2) and -1

OpenStudy (anonymous):

so that comes out to?

OpenStudy (anonymous):

the above are the the three values of x

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