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Let f(x)= 1/x^2. Find formula for f`(x) using definition of derivative. Thank you!
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\[\frac{\frac{1}{(x+h)^2}-\frac{1}{(x)^2}}{h}\]
with the lim h-->0?
yes
\[\frac{\left(\frac{-h^2-2 h x}{h^2 x^2+2 h x^3+x^4}\right)}{h}=\left(\frac{-h^2-2 h x}{h^3 x^2+2 h^2 x^3+x^4h}\right)=\left(\frac{-h-2\text{ }x}{h^2 x^2+2 h x^3+x^4}\right)\]
\[\lim_{h\to 0} \, -\frac{h+2 x}{h^2 x^2+2 h x^3+x^4}\]
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I don't understand... could you be more explicit? I'm really grateful for your help=)
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