Question

Find the zeros of the function f(t) = 2t^3 + 3t^2 + 8t +12

Answer 1

0=2t^3 + 3t^2 + 8t +12
0=(2t+3)(t^2+4)
0=2t+3 or 0=t^2+4
2t=-3 or t^2=-4
t=-3/2 and the square root of a negative number does not exist, so

t=-3/2

Answer 2

t^2=-4 has the solution t=2i or t=-2i