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Factor completely p4^4 – 8p^2 + 16
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Is that 4p^4?
Yes I mean, no, I'm sorry
It's p^4 **
(2p^2)^2 - 2(2p^2)(4) + (4)^2 = (2p^2 - 4)^2
p^4-8p^2+16 (p^2-4)^2
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Then the answer is (p^2 - 4)^2 = (p^2 - 2^2) = (p + 2)(p - 2)
sorry, small mistake, ((p + 2)(p - 2))^2
p^2 - 4 can be further factorised yellowranger.
Oh, good call. Thanks for noticing.
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