Question

solve sqrtx+3-3=x

Answer 1

is that \[\sqrt{x+3}-3=x\]?

Answer 2

Otherwise\[\sqrt{x} = x\] , suppose the answer could be 1

Answer 3

\[\sqrt{x+3}=x+3\]
\[x+3=(x+3)^2\]
\[x+3=x^2+6x+9\]
\[x^2+5x+6=0\]
\[(x+2)(x+3)=0\]

So x= -2 or x= -3.

Answer 4

If it is Will! it would be 1 or 0