Question

How to solve sin 2λ ?

Answer 1

that is not an equation

Answer 2

sin 2λ = 0

2λ = n.pi

λ = n.pi / 2 ----->>>> How do I get this...???

Answer 3

\[sin (2\lambda) =0\]
\[2\lambda = arcsin(0)\]
\[ \lambda = { arcsin(0) \over 2} \]

Answer 4

\[arcsin (0) =0+n\pi\] where n is an integer

Answer 5

graph y = arcsin(x)

Answer 6

How about arccos(0) ?

Answer 7

\[arccos{0}=\frac{\pi}{2}+n\pi\] where n is an integer