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OpenStudy (anonymous):
Solve using the square root method. x2 - 16 = 0
A. {-8, 8}
B. {-4, 4}
C. {8}
D. {4}
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OpenStudy (anonymous):
x2 means 2*x?
myininaya (myininaya):
i think she meant x^2
myininaya (myininaya):
it does say use the square root property
OpenStudy (anonymous):
no she asked this just now
myininaya (myininaya):
oh
i see
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myininaya (myininaya):
this is a repeat isn't it meow?
OpenStudy (anonymous):
x^2 my baddd
OpenStudy (anonymous):
No its not
myininaya (myininaya):
you just ask this question
myininaya (myininaya):
refer to the thread before this one someone gave you answer
but if you are looking for an explanation someone could provide that
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myininaya (myininaya):
add 16 on both sides
myininaya (myininaya):
then take the square root of both sides
myininaya (myininaya):
don't forget to put plus or minus
myininaya (myininaya):
Try not to post the same questions back to back pretty please.
OpenStudy (anonymous):
So confused :(
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OpenStudy (anonymous):
where
OpenStudy (anonymous):
the whole thing like the answer
jimthompson5910 (jim_thompson5910):
\[\Large x^2-16=0\]
\[\Large x^2=16\]
\[\Large x^2=\pm\sqrt{16}\]
\[\Large x=\sqrt{16} \ \text{or} \ x=-\sqrt{16}\]
\[\Large x=4 \ \text{or} \ x=-4\]
So the solution set is {4, -4}
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