Question

See attachment.

Answer 1

\[a^{12}*a^{0}=a^{12}*1=a^{12}\]

Answer 2

What can we do with the 12 and 0?

Hint: \[x^3 \times x^5 = x^8\]

Answer 3

so the answer is \[a ^{12}\]

Answer 4

Yes, because
\[a^{m}*a^{n}=a^{m+n}\]\[a^{12}*a^{0}=a^{12+0}=a^{12}\]

Answer 5

kk THX

Answer 6

no problem :)