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Mathematics 16 Online
OpenStudy (anonymous):

Simplify: (the dashed line is the fraction bar) -sin[(π/)-x] ----------- cos[(π/2-x]

OpenStudy (mertsj):

Is it -sin[pi/2)-x] in the numerator

OpenStudy (anonymous):

yes sorry lol

OpenStudy (mertsj):

Then the answer is -tan[(pi/2)-x]

OpenStudy (anonymous):

I'm given 6 answers (multiple choice): a) -1 (b) cos x (c) cot x d) 1 ( e) -tan x (f) sin x I got the same as you, but I'm not really sure what to put as the correct conclusion o,,O

OpenStudy (mertsj):

(e) - tan x

OpenStudy (anonymous):

OH, I did not get a negative, well thank you sir ;D

OpenStudy (anonymous):

or ma'am

OpenStudy (mertsj):

-sin/cos = -tan

OpenStudy (mertsj):

yw

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