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OpenStudy (anonymous):
y =
4
3
x + 3
y = −
2
3
x − 3
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OpenStudy (anonymous):
I am not sure what
y = −
2
3 x − 3
means?
OpenStudy (anonymous):
4 over 3times x plus 3 and negative 2 thirds times x -3
OpenStudy (anonymous):
systems of quations
OpenStudy (anonymous):
equations*
OpenStudy (anonymous):
y = (4/3)x + 3
y = (-2/3)x - 3
Let's use the subtraction method to get
0 = (6/3)x + 6
Okay with this?
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OpenStudy (anonymous):
subtraction method or substitution method?
OpenStudy (anonymous):
Let's use the subtraction method to get
0 = (6/3)x + 6
Okay with this?
OpenStudy (anonymous):
x=9?
OpenStudy (anonymous):
Hmmmm ......
0 = (6/3)x + 6
six divided by 3 is 2
0 = 2x +6
subtract 6 from both sides
-6 = 2x
x = ??
OpenStudy (anonymous):
y=6/3x+6 i got that far then stumble
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OpenStudy (anonymous):
Did you see my last post? I worked most of it out for you ...
0 = (6/3)x + 6
six divided by 3 is 2
0 = 2x +6
subtract 6 from both sides
-6 = 2x
x = ??
OpenStudy (anonymous):
i can't figure out x im getting like
OpenStudy (anonymous):
so y = -3?
OpenStudy (anonymous):
i meen x = -3
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