Question

If a pro basketball player has a vertical leap of about 35 inches, what is his hang time? use the hang time as a function V=48T^2

Answer 1

Is V = vertical leap?

Answer 2

yes
i think

Answer 3

\[T = \sqrt{V\div48}\]

Answer 4

is that the answer because i do not know how to do this problem?

Answer 5

does anybody else know what to do?

Answer 6

Given that v is the vertical leap and t is the time you're looking for.
Sub in v so that... \[t = \sqrt{35/48} = 0.85391256 seconds\]