Question

I'm trying to solve the integral x/(1-x^2)^(1/2) dx I have u=x du=dx dv=1/(1-x^2)^(1/2) v=2(1-x^2)^(1/2)?
Please let me know if I'm on the right track.

Answer 1

not quite
simple u-substitution
u=1-x^2
du=-2xdx
integrate.

Answer 2

thanks so much. I didn't see a reply that's why I sent out the same question several times, and went to sleep. A simple u-substitution does make sense. Thanks again