Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Explain a fast and easy way to factor.

OpenStudy (mertsj):

To factor what? I don't think anybody is going to write a chapter on factoring.

OpenStudy (anonymous):

Just the basic steps of factoring is all I'm looking for. Maybe some tips that you have that has helped you with factoring.

OpenStudy (mertsj):

1. Whatever it is, look for a common factor and factor it out if there is one. 2. Is it a binomial, trinomial or four terms? 3. If it's a binomial, is it the difference of two squares. If not, you can't factor it. 4. If it's a trinomial try to factor it as the product of two binomials. ( )( ) 5. If it has 4 terms, try to factor by grouping.

OpenStudy (anonymous):

Thank you! That will help me alot.

OpenStudy (mertsj):

yw

OpenStudy (anonymous):

are you factoring multiple terms or is this simple GCF LCM

OpenStudy (anonymous):

theres a couple 'tricks' to both

OpenStudy (mertsj):

We're all ears.

OpenStudy (anonymous):

which is it?

OpenStudy (anonymous):

Well for example I had this, 3x^2+22x-16=0 I used to be able to do this in a good amount of time but I'm out of practice and I've forgotten alot. I also have this, x^2-9x+14/4x=0

OpenStudy (anonymous):

Finding the zeros of the function by factoring.

OpenStudy (mertsj):

3x^2 +22x -16 is a trinomial so try two binomials clearly one would have to start with 3x and the other with x (3x )(x )

OpenStudy (mertsj):

The 16 on the end is negative. possible factors of -16 are 1, -16 -1, 16 -2,8 2,-8 4,-4

OpenStudy (mertsj):

Use trial and error with those factor pairs until you find the one that gives the correct middle term.

OpenStudy (mertsj):

Did you get (3x-2)(x+8) ?

OpenStudy (anonymous):

Yes, I just got that. So now I put (3x-2) equal to zero?

OpenStudy (anonymous):

Thank you for the help! I finished the problem and got x=2/3 and x=8

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!