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what is the derivative of following dx/dt=? dy/dt=? dz/dt=? x=sine^t y=cose^t z=Underoot3 e^t
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\[z=\sqrt{3}e ^{t}\]
sin^t of which variaable ??
given is t dear
i wrote the question same which is written
that is sin e^t
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oh its easy ...... the answers are as follows : dy/dt is \[e^{t}\cos(e^{t}) \] dy/dt = \[-e^{t} \sin (e^{t}) \] dz/dt = \[\sqrt{3}e^{t}\]
thnks
wlcme
in the future, when you dealw ith these partial differentiations, you need to specify that it is one
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