Question

find all the rational zeros of the function
f(x)=6x^4-18x^3-318x^2-54x

Answer 1

0 is obivious

Answer 2

since we took zero out , lets divide by (x-0)=x

6x^3 -18x^2-318x-54

Answer 3

Okay so then?

Answer 4

Im sorry I just do not get math at all

Answer 5

divide every factor of 54 by every factor of 6

\[\frac{\pm1,2,3,6,9,27}{1,2,3,6}\]

so try 9

6(9)^3 -18(9)^2-318(9)-54=0 yes

Answer 6

so it would be (0,9)?

Answer 7

answers are 0 and9

Answer 8

Okay thank you :)