Question

[4,4 1,-5]

Answer 1

What would you like to do with this matrix?

Answer 2

I need to find the inverse

Answer 3

It is not a square matrix; there it does not have an inverse.

Answer 4

\[{{ab}\choose{cd}}^{-1}=\frac{1}{ad-bc}{{d(b)}\choose{(c)a}}\]
and (b) and (c) are just the negatives.