The following system is solved by substitution. Which expression is substituted for z in the second and third equations?

x + 5y – z = 6
3x – y – 2z = 4
3x – 2y + 3z = 13

ANSWERS :

–x – 5y – 6
x + 5y – 6
–x – 5y + 6
x + 5y + 6

Question

The following system is solved by substitution. Which expression is substituted for z in the second and third equations?

x + 5y – z = 6
3x – y – 2z = 4
3x – 2y + 3z = 13

ANSWERS :

–x – 5y – 6
		x + 5y – 6
		–x – 5y + 6
		x + 5y + 6

amistre64 · Answer

its easier to me to just add z and subtract 6 from the first eq ...

anonymous · Answer

ADD z to what ?

amistre64 · Answer

x + 5y – z = 6
           +z    +z
-------------
x + 5y + 0 = 6 + z
            -6    -6
----------------
x + 5y -6 = z

amistre64 · Answer

add it to both sides of the equation ...