Question

I'm having a hard time finding that m 14 years ago

Answer 1

See attached

Answer 2

I have filled-in the angles that can be worked out directly and labelled the rest as follows:

m<BCA = m<CBE + m<CEB (external angle of a triangle)
75 = alpha + beta <--- (1)
m<BCA + m<BCD + m<DCE = 180 (angle on a straight line)
75 + 180 - 2alpha + beta = 180
75 = 2alpha - beta <--- (2)

2*(1) - (2) gives:
75 = 3beta
25 = beta