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I have filled-in the angles that can be worked out directly and labelled the rest as follows: |dw:1325721373971:dw| m<BCA = m<CBE + m<CEB (external angle of a triangle) 75 = alpha + beta <--- (1) m<BCA + m<BCD + m<DCE = 180 (angle on a straight line) 75 + 180 - 2alpha + beta = 180 75 = 2alpha - beta <--- (2) 2*(1) - (2) gives: 75 = 3beta 25 = beta
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