Find the perimeter of a rectangular object which has a length of a square root of 128ft and a width of square root 200ft.

Question

Find the perimeter of a rectangular object which has a length of a square root of 128ft  and a width of square root 200ft.

anonymous · Answer

i got an product of 160 is this correct i think it is but not sure

anonymous · Answer

45.24?

anonymous · Answer

square root of 128 is 22.62

anonymous · Answer

perimeter is length times width so im guessing sqrt 128 times sqrt 200 will give me the correct answer.

anonymous · Answer

after i't been multiplied by 2

anonymous · Answer

50.90

anonymous · Answer

sqrt 128 times sqrt 200 = sqrt 160  
then the simplified radical form is 4 sqrt 10 thats wat i got wat do u think?

anonymous · Answer

$$\sqrt{128} \times \sqrt{200}$$

anonymous · Answer

$$\sqrt{128} \times \sqrt{200}=\sqrt{160}=4\sqrt{10}$$

anonymous · Answer

correct? i know how to do it its just i need to verify if this is right cuz the question is kinda long it has 4 parts