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Daniel has 8 wire panels that he will use as the side of a new cage for his guinea pig, oscar. Each panel is 1 foot long a) If he make the length of the base of the cage 3 feets and its total area will be 3 square feet,what will be width of the base of the cage be? Show work b) If he instated made all of side of the base 2 feet long, would Oscar have more room?.Shoe your work.
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Cage width will be 1 foot and length, 3 feet. The perimeter will be 8 feet long, 2*1 + 2*3 = 8. From Mathematica: Maximize [ { L*w, 2*L + 2*w == 8 }, { L, w } ] -> { 4, { L -> 2, w -> 2 } }
a l*w=A, 3ft=length 1ft= width 3*1= total area 3 ft b l*w= A if all sides of the base were 2 ft 2ft *2 ft= 4ft more room than 3 ft
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