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simplify the expression sin x(csc x-sin x)
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\[\cos ^2x\]
\[b(\frac{1}{b}-b)=1-b^2\]
then \[1-\sin^2(x)=\cos^2(x)\]
\[=\frac{sinx}{sinx}-sin^2x=1-sin^2(x)=cos^2x\]
1) Distribute 2) sin multiplied by csc is 1 (reciprocal identity) 3) sin multiplied by sin is sin ^ 2 4) 1-sin^2 = cos^2 (basic identity)
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thank you so much that helped a lot.
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