Question

y varies directly with the square of p and inversely with the square root of q. If
y =6when p = 4 and q =16 , find y when p = 8 and q = 4 .

Answer 1

\[6=k(4)^{2}/\sqrt{16}\]\[y=kp ^{2}/\sqrt{q}\]

Answer 2

4k = 6 and k = 1.5