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Prove that a parallelogram with 2 congruent diagonals is a rectangle.
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Consider it as though the diagonals are the hypotenuses of two right triangles and if the hypotenuses are equal, then the legs must be equal too.
Prove using congrunecy of triangles in a parallelogram diagonals bisect each other take two adjacent triangles and since diagonals are equal the two triangles are congruent hence you get that its a rhombus as sides are equal to prove angle is 90 just take the two parallel sides and apply properties to get it. Its not too hard i suppose.
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