A trapezoid is drawn on a grid with vertices at P (-5, 7), Q (-2, 7), R (2, 3), and S (-8, 3). Trapezoid UVWX will be drawn similar to Trapezoid PQRS with side UV corresponding to side PQ. The point (2, -2) will be the location of vertex U and point (8, -2) will be the location of point V. What will be the coordinates of vertex X? Show all your work or explain your reasoning.
please help
if its similar then it differs by some scalar what is the distance from P to Q?
P to Q is 3 units
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what is the distance fron U to V then to compare with ?
X will be similarly positioned to S at the same offsets. So, you need to calculate the offset from P to S (y and x) and add that to U to get the coordinates of X.
u to v is 6 units
good, since our original is 3 units; and our new one is 6 units; this tells us that each side of the new trap is bigger by a factor of 2. 3 times 2 = 6 i would grow the old one by a factor of 2 then move it
all the linear aspects are bigger by a factor of 2; up and down, left and right; criss and cross
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