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sqrt(49 * 4 *-19*13) the equation has 2 real solutions
ax^2+bx+c=0 Discriminant D=b^2-4ac 13x^2+7x-19 D=49-4*13*(-19) D=1037 D=1037 so equation has two real solutions
( i couldn't find my calculator)
also i should not have wrote sqrt!!!
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\[x = 1/26 (\sqrt(517)-7)\]
\[b^2-4ac=7^2-4(13)(-19)>0\] The solution will be two real numbers.
\[1/26 (-7+\sqrt(517))\] two real solutions
Brain has officially left the building. \[\Large {7^2} - 4(13 \cdot - 19) = 49 + 988 = 1037\]
ok so it'll be choice B? Then what to i put in the box.
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1037
D=1037
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