Question

What are the x- and y-intercepts of the graph of y = 2x^2 - 8x - 10

x-intercepts: (1, 0) and (-5, 0)
y-intercept: (0, 10)

x-intercepts: (-1, 0) and (-5, 0)
y-intercept: (0, 5)

x-intercepts: (-1, 0) and (5, 0)
y-intercept: (0, 5)

x-intercepts: (-1, 0) and (5, 0)
y-intercept: (0, -10)

Answer 1

To find x-intercepts, set y=0 and solve for x
To find y-intercepts, set x=0 and solve for y

Answer 2

meaning without doing much work at all you can rule out the top three

Answer 3

because finding y-intercept is easiest! :)

Answer 4

set x=0, what does y=?

Answer 5

y=2x^2-8x-10
for y intercept put x=0
y=-10
so y intercept is (0,-10)
for x intercept put y=0
and solve for x
0=2x^2-8x-10
divide by 2 the whole equation
x^2-4x-5=0
find factors of -5 which have a difference of -4
-5 and 1
x^2-5x+x-5=0
x(x-5)+1(x-5)=0
( x+1) (x-5)=0
x=-1 and 5
so x intercept (-1,0) and (5,0)