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Paul throws a baseball onto the field. The baseball leaves Paul’s hand with an initial upward velocity of 15 meters per second. If the baseball is 1 meter off the ground when it leaves Paul’s hand, about how long will it take for the baseball to hit the ground? Round your answer to the nearest tenth.
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s = -1, u = 15, t = ?, a = -9.8 m/s/s s = ut + 0.5 at^2 -1 = 15t + 4.9t^2 4.9t^2 + 15t + 1 = 0 solve for t
sorry - typo \ equation should be 4.9t^2 - 15t - 1 = 0
t = 3.1 secs to nearest tenth second
r u there cherry?
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