Question

whats the order of (dy/dx)^5 + (d^2y/dx^2) +1=0 ?

Answer 1

what do you think ?

Answer 2

and why?

Answer 3

its always first question in tests

Answer 4

i think its second order

Answer 5

you are right

Answer 6

why they put the stupid power near dy/dx xd

Answer 7

that's not power , it means taking derivative twice

(dy/dx)^5 + d/dx((dy/dx)) +1=0 ?

Answer 8

in different notation, it would look like this

(y')^5 + y'' +1 =0

Answer 9

so we are multiplying y' 5 time?

Answer 10

yes

Answer 11

thnx 0.5Point of test just earned.