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(x-9/7)(x+7/9)
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x^2-16/63 thats as far as i have gotten
whats (-9/7)(7/9) ?
x^2+(7/9-9/7)x-(-9/7)(7/9) =x^2 - (32/63)x - 1
Here is the method I was taught to expand brackets
\[(x-\frac{9}{7})(x+\frac{7}{9})=x^2+\frac{7x}{9}-\frac{9x}{7}-\frac{9*7}{7*9}\] \[=x^2+\frac{49x}{63}-\frac{81x}{63}-1\] \[=x^2-\frac{32x}{63}-1\]
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