Question

write an equation in slope-inyercept form for the line parallel to y=5x-2 that passes through the point (8,-2)

Answer 1

OK, so first you are going to figure out the slope of your new line, which being parallel to line y = 5x -2 would give your line a slope of 5.

Next you put your equation into point slope form\[y - y _{1} = m (x -x _{1})\]

y+2 = 5(x-8)

and simplify

y + 2 = 5x -40

Then you convert it to slope intercept

y = mx + b

y = 5x -42

This should be your answer

Answer 2

Since we have the slope, which is 5 just use the y intercept form and plugin your points
y = mx + b
-2 = 5(8) + b
-2 = 40 +b
-40-2 = b
-42 = b

Now that we have b, which is the y intercept point we can write the equation of the line in slope intercept form

y = 5x - 42

Answer 3

good ^