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OpenStudy (anonymous):
how about this? find f'(x) of f(x)=√x / (1+x^2)... I used quotient rule but it's kinda weird..
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OpenStudy (anonymous):
\[x^{1/2}(1+x^2)^{-1}\] use product and chain rule
OpenStudy (anonymous):
tq sooo much! really help me ...
OpenStudy (anonymous):
i got -4x+1 / (1+x^2) (2√1+x^2 )... is it?
OpenStudy (phi):
you can use wolfram to check your work http://www.wolframalpha.com/input/?i=d%2Fdx+sqrt%28x%29+%281%2Bx%5E2%29%5E-1
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