Question

Hello~Can someone help me with this math problem please and thanks in advance.

find the indicated outputs for f(x)=2 to the 2nd power-5x
f(0)=
f(-1)=
f(2)=

Answer 1

\[f(x)=2^{2}-5x\]

Answer 2

Is that it?

Answer 3

almost
2x to the second power

Answer 4

How did you do that

Answer 5

I used the equation writer right below this box where it says equation.

Answer 6

ohhhhhh
thank you` I'm a newbie on here

Answer 7

\[f(x)=2x ^{2}-5x\]

Answer 8

Is that it?

Answer 9

yes

Answer 10

So to find the f(0) replace x with 0. What do you get?

Answer 11

0?

Answer 12

oh wait for all of them?
Let me try

Answer 13

Yes. So f(0) = 0 and that is the ordered pair (0,0)
Now find the f(-1) by replacing x with -1

Answer 14

ohhhhhh- Thank you very much

Answer 15

What did you get?

Answer 16

yw

Answer 17

One moment-I'm still trying here :-)

Answer 18

I got 20, but it is suppose to be an ordered pair right?

Answer 19

(-4,5)?

Answer 20

f(x)=2x^2-5x
f(-1)=2(-1)^2-5(-1)
f(-1)=2+5=7

Answer 21

That would give us the ordered pair (-1,7)

Answer 22

Oh

Answer 23

I'm going to look at your response to figure it out, I was way off

Answer 24

Now find the f(2) by replacing x with 2:

f(x)=2x^2-5x
f(2)=2(2)^2-5(2)
f(2)=8-10
f(2)=-2
So the ordered pair is (2,-2)

Answer 25

for the first one how did you get the -7. I see how you got the -1. Oh wait you added the 5 and 2, correct?