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-2x^2+9x+5<0
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the answer is: (-2x-1)(x-5)<0 -2x-1<0 x-5<0 -2x>1 x>5 x>1/-2# x>5#
that was good but u r wrong in the x>1/-2 it is x<1/-2
The answer is \( \left.x<-\frac{1}{2}\right\|x>5 \)
\[x\in \left(-\infty;-\frac{1}{2}\right)\cup\left(5;+\infty\right)\] :P
owh...im sory...im so careles
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