Question

x^2-x 14 years ago

Answer 1

(1,0)

Answer 2

x^2-x=0
x(x-1)=0
->x=0 or ->x=1

Answer 3

\[ 0\leq x\leq 1 \]

Answer 4

After you find the x values.
Sub in values either side to determine the inequality direction.

Answer 5

ou cant include 1 and 0

Answer 6

\[x^2 -x \le 0 \rightarrow x(x-1) \le 0\]

+ 0 - 1 +


[0,1]

Answer 7

Yes, you can include 1 and 0. You must.

Answer 8

yeah, i missed that equal to

Answer 9

the s.s={x:-1<or=to x <or=to2} u ( )
or[-1,2]