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Suppose that you want to move a heavy box with mass 30.0 across a carpeted floor. You try pushing hard on one of the edges, but the box does not move. Suppose that you are pushing against the box from an angle 30.0 above horizontal with a force of magnitude 240 . What is the magnitude of the friction force acting on the box?
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and also for the normal force... thanks. :)
Since the block does not move friction force=horizontal force applied.(Newtons law F=ma,a=0 Net F=0), So horizontal force would be 240 cos30 and nromal force would be 240sin 30. You need only horizontal force=120sqrt(3).
oh.. ok.. got it shankvee. thanks. :)
No probs. :)
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