Question

graph the following equation and state the center radius and x- and y- intercepts if they exist
(x+3)^2 + (4-2)^2) =4

Answer 1

i bet it is
\[(x+3)^2 + (y-2)^2=4\]

Answer 2

circle with center (-3,2) and radius 2

Answer 3

So no y-intercept, and tangential x-intercept at x=-3.