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evaluate limit lim_x approaches 4 (x-4)^3/l 4-x l
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\[lim_{x \rightarrow 4} \frac{(x-4)^3}{| 4-x |}\]like that?
yes
that would be zero
pliz help me
how to show ?
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\[|4-x|=|x-4|=\sqrt{(x-4)^2}\] you can divide by this to get \[(x-4)^2\] and that limit is certainly zero
ok tq
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