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OpenStudy (s):
[(x^3) - (y^3)]dx + [(y^3) - 3x(y^2)]dy = 0 I. M = x^3 - y^3 ; N = y^3 - 3x(y^2) II. ?
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OpenStudy (anonymous):
I hope this is exact
OpenStudy (anonymous):
M dx + N dy check dM/dy= dN/dx
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