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6x-2y=32 4x-2y=18 solve?
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can you make it so that one of these equations just looks like this? y = ____
Subtract the second equation from the first and solve for x
mathmate's approach would work as well you can subtract them and then you will know what x will be
i'm sorry but can someone walk me through?
ok, let's start by subtracting the second equation from the first: 6x-2y=32 ...(1) 4x-2y=18 ...(2) (1)-(2) 6x-4x=32-18, => 2x=14 => x=7 Now put x=7 in equation (1) 6(7)-2y=32 42-2y=32 2y=42-32=10 y=10/2=5 So x=7, y=5
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